The Power of challenge, need help on the last part

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ebb
Posts: 2
Joined: Sat Nov 08, 2008 1:13 pm

The Power of challenge, need help on the last part

Post by ebb »

I calculated the number with my Texas Instruments Voyage 200 calculater (its a very very long number :D)

After that i sorted the number in 33 digit blocks like:
1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3
2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4
6 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 5
......


then i tooked the last digit and put them together: 345 .... in this example

is that the right way ? cause it's not working, can you give me a hint ?

greez
ebb
cyberwoozle
Posts: 60
Joined: Fri Nov 07, 2008 10:43 am
Location: Germany

Post by cyberwoozle »

Read exactly, what you have to do !!!
tails
Posts: 191
Joined: Tue Jun 10, 2008 7:51 pm
Location: Tokyo

Re: The Power of challenge, need help on the last part

Post by tails »

Close, but why do you take last numbers?
ebb
Posts: 2
Joined: Sat Nov 08, 2008 1:13 pm

Post by ebb »

most significant ......
I'm a stupid guy *fg*


thanks


greez
ebb
jeetee
Posts: 105
Joined: Sun Jan 04, 2009 5:25 pm

Post by jeetee »

I'm solving this one using gcalctool on ubuntu, and I get a 6-digit number for the answer. However submitting it (manually, using the form on the site) tells me my answer isn't correct.

If it indeed is not, then it might be that gcalctool truncates the answer and I should use a different tool. So if anyone could just tell me if the correct answer is 6 digits or not, that would be a great help.

If the answer indeed is a 6-digit number, then I'm stumped :p
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