Didactic Long XOR challenge
Didactic Long XOR challenge
For those having a hard time with this challenge. Unless it gets changed, there is more to this challenge than is stated in the problem.
I don't exactly understand "the same cipher as in Didactic XOR 2" and how to turn it into a four-byte cipher.
I have tried the answer to XOR 2, which is a word of n letters, taking the first four letters as cipher. But that didnt work.
And i have tried the cipher from XOR 2, which is a single byte value, filled up with leading zeros to become a "four-byte cipher". But that didnt work either.
I guess im lost
I have tried the answer to XOR 2, which is a word of n letters, taking the first four letters as cipher. But that didnt work.
And i have tried the cipher from XOR 2, which is a single byte value, filled up with leading zeros to become a "four-byte cipher". But that didnt work either.
I guess im lost
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- Posts: 61
- Joined: Wed Apr 30, 2008 3:31 am
ok, sorry i trusted "wc -m" without checking "echo 1 | wc -m" so now i know that i have to suntract 1 from the result. so there are 212 bytes. so it has to work also for me and i have to think further about this problem.the_impaler wrote:Are you sure ? I didn't count myself but groovy script said it's 212muffi wrote:my problem with didactic xor long cipher is that the hex-word is 213 bytes long. imo 213 mod 4 =1.
what can i do with that damned 1 byte i cannot decrypt to a full character.