hacker.org

dotme

Would be funny to change all passwords of acounts who didn't yet. They can recover it by "Lost password".

dotme

m!nus wrote:there was a reason noone posted that link

hrhr

dotme

Passwords should still be updated. (for email too if you happen to use the same password) That should be emphasized ! People using the same combination of username/email and password for common web-services should change their passwords immediatly!!! I would also recommend suspending accounts at ha...

dotme

days since starting (0) to play that puzzle?

dotme

I hate KISS, but after my first attempt to modify "blockDied" failed, I went the same way like tog - making all borders to bounce and left the applet alone.
Changing the levels so that they consist only of one block showed that the solution seems to be based on the number of blocks?!

dotme

Hmm, I expected this to be harder. My 1st idea was to decrement both values in a loop and break out when the first number falls to zero. But before testing this solution I thaught about the cycle limit and potentially negative values and discarded that idea. But as I didn't had an idea how to test f...

dotme

I just filled in the values and reformed the equation 8841 = 79 * 2245 + (79 * 2 - 7); 8841 = 79 * 2245 + 151; // - 151 8690 = 79 * 2245 // / 79 110 = 2245 Than the solution was obvious how to modify "2245" to solve this equation. It was likely that the first term "79 * 2245" has...

dotme

That was fun. While solving "Big Fib" with bc driven by a perl-script and using the dijkstra-simplification, I realized that getting the solution for this challenge would take more time and cycles than I want to spent on it. So, I changed to C with GMP and was really thrilled by the speed ...

dotme

If it were client time then you could spoof the packets ... Normally, HTTP doesn't expect that the client sends a "Date" header with the request. So, I don't think the server cares about one, if given. Anyway, I solved it and asked myself afterwards if I missed any hint on what time the o...

dotme

I turned the program into a for-loop starting with 1 and solved it with that perl-snippet

Code: Select all

my $depth;
my $cc = 1;
for ( $depth = 1; $depth <= 11589; $depth++ ) {
    $cc = $cc + ($depth % 7) + (((($cc ^ $depth) % 4) == 0) ? 1 : 0);
}
print $cc, "\n";

hacker.org

Search found 10 matches

Broken Key

Bigger Fib

Re: client or server time