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Look at sig.
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hmm, i got similar (probably the same) mathematical closed form formula (see it in my first post, writen in Mathematica syntax) but i was not sure how to mathematically calculate the int overflow. I see you used mod 2^32, but that won't explain how you get negative answers, which happens with int ov...

that one was pure evil ... first i wasted bunch of hours installing disassemblers which looked completely uncomprehensible to me... almost broke my virtual xp installation with softice. Then I decompiled with RemoteSoft samander and figured out the loops. Just when i figured out the exact value for ...

alright so I solved but I am not happy with the solution. I don't know much about SQL so basically used the code from here http://sqlzoo.net/hack/ and automized it with python... Of course since the password field for forced entry seems to escape special characters I just used the Secure Room form. ...

yeah i did the memory cheater at the end, but i just wished there was way to edit bytecode that javad spits out and run it as if it was say python program. Without any messy hex and such...

I tried very similar things but with lives variable, but somehow it never ran after i tweaked the code. I suspect the code for the lifes was seriously obfuscated since I changed MAXLIVES but nothing happened. What software did you guys use for editing bytecode? I tried some terrible homebrew softwar...

So anybody else thinks the "clarification" in parenthesis for what not to do is actually the same as the problem?!? Here is my python code, since the problem was small enough there was no issues with recursion depth or speed. draws=0.0 game=0.0 def move(L,player): global draws,game if(L[0]...

damn, i installed like 5 such programs but neither allows me to reverse. I guess assuming you can see those damned things it would be an useless feature.

just a brief warning to anybody stuck on breakout extreme... Forget about bytecode look into memory editting. I lost 10 hours reading about java bytecode commands and trying to get a good bytecode editor. However the obfuscation software made the bytecode such a mess that it was near impossible. Plu...

I believe one of the challenges involves a stereogram ... however I have never been able to see in one of those things ever. Anyone has some good tutorials or software for that sort of thing.

In case the admins are wondering about why I went though the maze two times, and the first time completely covered the whole maze...my program was looking for the string "edge" and considering it as a falure... which was quite unfortunate when it was contained in the password :) btw, I was...

yeah i tried to sum it up in python but regular float didn't have enough percision, or maybe i should have just started summing it up from the smallest to the biggest ... Anyways the ratio N/D actually is a converging sum. So I just used the convergent value which is (1+7pi/8 ), now the answer for e...

As a mathematician I really enjoyed that one. I guess the best way to solve it is to realize that the number is question is connected to the infinite sum 1/1/3+1/5/7+1/9/11+1/13/15+.... I used mathematica which instantly spit out that the answer is pi/8, so I am wondering whats the best way to prove...

I just solved this one but still have no idea what "newsgroup" means or what the clues given are supposed to tell you. All I can say is get a crypto book and read the first few chapters.