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The Power of challenge, need help on the last part

Posted: Sun Nov 09, 2008 5:19 pm
by ebb
I calculated the number with my Texas Instruments Voyage 200 calculater (its a very very long number :D)

After that i sorted the number in 33 digit blocks like:
1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3
2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4
6 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 3 4 5 6 7 8 9 0 1 2 5
......


then i tooked the last digit and put them together: 345 .... in this example

is that the right way ? cause it's not working, can you give me a hint ?

greez
ebb

Posted: Sun Nov 09, 2008 6:26 pm
by cyberwoozle
Read exactly, what you have to do !!!

Re: The Power of challenge, need help on the last part

Posted: Sun Nov 09, 2008 10:42 pm
by tails
Close, but why do you take last numbers?

Posted: Mon Nov 10, 2008 6:22 pm
by ebb
most significant ......
I'm a stupid guy *fg*


thanks


greez
ebb

Posted: Wed Jan 07, 2009 2:30 pm
by jeetee
I'm solving this one using gcalctool on ubuntu, and I get a 6-digit number for the answer. However submitting it (manually, using the form on the site) tells me my answer isn't correct.

If it indeed is not, then it might be that gcalctool truncates the answer and I should use a different tool. So if anyone could just tell me if the correct answer is 6 digits or not, that would be a great help.

If the answer indeed is a 6-digit number, then I'm stumped :p