hacker.org

Code: Select all

summe = (2118**2 + 2118)/2
for i in xrange(1, 47):
    summe += i**2
print summe

Code: Select all

x = 0
y = 1
while y < 2119 do
	x = x + y
	#machine to check if whole number
	def whole?(x)
		(x - x.floor) == 0
		end
	z = Math.sqrt(y)
	if whole?(z) == true
		x = x + y
		end
	y = y + 1
	end
puts x

Code: Select all

package hacker.org;

import java.util.regex.Pattern;

public class Delegates {

	public static void main(String[] args) {

		int sum = 0;
		for(int i=1; i<=2118; i++) {
			if(Pattern.compile("(.0)$").matcher(Double.toString(Math.sqrt(i))).find()) {
				System.out.println(i); //for me hh
				sum += 2*i;
			}
			else sum += i;
		}
		
		System.out.println("Sum : " + sum);
		
	}

}