Search found 3 matches

Go to advanced search

by Bo
Fri Apr 25, 2014 9:37 pm
Forum: Challenges Solved
Topic: Didactic XOR Cipher 2
Replies: 15
Views: 2375

one more c++ solution. FILE *f = fopen("output.txt","w"); string s = "948881859781c4979186898d90c4c68c85878f85808b8b808881c6c4828b96c4908c8d97c4878c858888818a8381"; for(int KEY = 0x10; KEY<=0xff; KEY++) { for(int i = 0; i< s.size();i+=2) { stringstream str; string byte ...
by Bo
Fri Apr 25, 2014 9:18 pm
Forum: Challenges Solved
Topic: Didactic XOR Cipher
Replies: 1
Views: 309

Code: Select all

for(int i = 0; i< s.size();i+=2)
	{
		stringstream str;
		string byte = s.substr(i,2);
		str << byte;
		int num(0);
		str >> std::hex >> num;
		printf("%c",(num^KEY));
	}
	cout<<endl;
by Bo
Fri Apr 25, 2014 8:43 pm
Forum: Challenges Solved
Topic: Didactic XOR Cipher
Replies: 1
Views: 309

how the hell should i guess that answer was in ASCII? correct answer is 72616e646f6d2073656564 in hex and i ve got it in like 5 min, but lost an hour to figure out the answer format. c++ there printf("%c%c%c%c%c%c%c%c%c%c%c%c", (0x3d ^ 0x4F), (0x2e ^ 0x4F), (0x21 ^ 0x4F), (0x2b ^ 0x4F), (0...

Go to advanced search