Search found 10 matches
- Thu Sep 19, 2024 6:07 am
- Forum: The Hacker's Server
- Topic: hacker.org revival
- Replies: 9
- Views: 17569
Re: hacker.org revival
This "project" is already dead, but nonetheless (it doesn't even build, NPM ftw): Without the Sources for the Challenges (including answers) it's not feasible to relaunch. I've been pondering it too at times This site is a fun introduction to the process of programming, so i liked to toss ...
- Mon Jan 09, 2023 11:26 am
- Forum: Challenges Solved
- Topic: Compression
- Replies: 14
- Views: 1771
- Tue Nov 01, 2011 8:38 pm
- Forum: Challenges
- Topic: Big Fib
- Replies: 36
- Views: 50139
- Fri Jun 24, 2011 9:38 pm
- Forum: Challenges Solved
- Topic: lotsa dots
- Replies: 26
- Views: 2267
- Mon Nov 22, 2010 7:30 pm
- Forum: Challenges Solved
- Topic: Once Upon A Time
- Replies: 11
- Views: 989
tried archive.org with http://www.hacker.org/challenge/top.php .... Of course, it didn't work :doh:
- Sun Nov 21, 2010 9:11 am
- Forum: Challenges Solved
- Topic: Your Turn
- Replies: 11
- Views: 978
Code: Select all
<?php
echo $_GET['out'];
?>
- Sun Nov 21, 2010 1:31 am
- Forum: Challenges
- Topic: Once upon a time
- Replies: 24
- Views: 36257
- Sun Oct 17, 2010 3:46 pm
- Forum: Challenges Solved
- Topic: Didactic Red
- Replies: 4
- Views: 642
- Sat Oct 16, 2010 11:06 pm
- Forum: Challenges Solved
- Topic: Substitute Teacher
- Replies: 28
- Views: 2667
Since i didn't have any idea of cryptography till today and im not an native english speaker, it wasn't an easy task. Took me good 2 hours to finish this one, but i had fun :) I made a little page to help me keep track of my substitutions: Right now it's also accessible at http://web-werker.de/tmp/c...
- Sat Oct 16, 2010 10:06 pm
- Forum: Challenges Solved
- Topic: The Powers That Be
- Replies: 27
- Views: 3096
And I know now how to do it in PHP.DocJoe wrote:Nice challenge. Now I know how to do large number multiplication in python.
Code: Select all
$x = bcpow(bcpow(17, 39), 11);
for($i = 0; $i < strlen($x); $i++) {
echo $x[$i];
if(($i+1) % 33 == 0) echo "<br />";
}