hacker.org

Could somebody please tell me how the original SQL-statement looked like? I solved it with this string: http://www.adum.com/fortknox/index.php?name=admi'%20UNION%20SELECT%20password%20FROM%20user%20WHERE%20'1'='1 admi' UNION SELECT password FROM user WHERE '1'='1 I got to know that the table is call...

I know how the table and three columns are called. I know the number of selected rows. I know that the user 'admin' exists. But I have no idea how to solve this challenge

edit: Never mind, I got it.

Is it enough to solve the 20,000-for-loop to a multiplication and an addition? Or is more tweaking required? It just runs. I think I let it try for 30 min (so until 18:25).

This one took me quite long and I analyzed much more than this. I thought the size might be ok and checked many other things ... but a post in the forum got me back on the right track.

Thanks bsguedes got it.

Well, I found the PNG (Portable Network Graphics) Specification, Version 1.2 . [edited because DaymItzJack though I would give too much information] But my hex-editor has no possibility to jump to a certain byte and I don't want to count up to [edited]. Do you know a good hex editor for Linux (GNOME...

Are we supposed to find the one byte which is wrong by hand?

wolfram|alpha for the number, FF + Modify headers + Range:bytes=999999999999999999999999999999999999999999999999999-100000000000000000000000000000000000000000000000098 By the way, someone has asked for the answer on stackoverflow: http://stackoverflow.com/questions/6180826/retrieving-part-of-the-pag...

Hi,

a few minutes ago I got an Internal Server Error. Could you please explain why?

By the way, the message that appears can be customized. At the moment, the standard message tells you to inform webmaster@hacker.org, but this email-adress doesn't exist.

Cheers,
moose

# My current level: 128 (4883 XP) # dungeon level: 123 # HP: 2640 # Weapon: Level 122 Slicer +5 (Strength: 127) # Inventory: Aquamarine potion +4, Aquamarine potion +5, Magenta potion +4 I hope it will summon soon... edit: Never mind, I got it :D That was easy ... hat more than 2000 HP and the +5 he...

So I guess I have to combine it with another method. At the moment I have a lot of characters (well ...2 different ones - 0d, 0a - but they occur quite often) which do not make any sense to me. I guess case sensitivity is important?
I have no clue how to continue ...

It's in the crypto-category. Is it a common encryption or a self-invented one?

Here is my Python-solution: import re #thanks to http://stackoverflow.com/questions/937697/can-you-pass-a-dictionary-when-replacing-strings-in-python def dict_sub(d, text): """ Replace in 'text' non-overlapping occurences of REs whose patterns are keys in dictionary 'd' by correspondi...

@gfoot: Thank you very much. I simply made a for-loop over every possible input for bucketFromRandom, but I couldn't guess whats wrong.

I took a look at the picture and found a "secret" text in it. But it seems to be latin (look quite like lorem ipsum, but as I don't understand latin I'm not sure).

Is the text we are suposed to find in this image in English? Is there more than the chaotic text and the lorem ipsum text?